p^2-11p-60=0

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Solution for p^2-11p-60=0 equation: 



p^2-11p-60=0

a = 1; b = -11; c = -60;
Δ = b2-4ac
Δ = -112-4·1·(-60)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-19}{2*1}=\frac{-8}{2}
=-4
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+19}{2*1}=\frac{30}{2}
=15
$

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